Hi all- just wanted to have someone else check behind me and point any flaws out in my reasoning.
Task asks: "Configure a one line standard access-list on R6 to filter out all routes coming from BB1 that have an odd number in the third octet"
My solution:
access-list 1 permit 200.0.0.0 0.0.2.255
Using my solution, before applying the distribute-list:
Rack1R6#sh ip route | i 54.1.1
D 200.0.0.0/24 [90/2297856] via 54.1.1.254, 00:02:52, Serial0/0/0
C 54.1.1.0 is directly connected, Serial0/0/0
D 200.0.1.0/24 [90/2297856] via 54.1.1.254, 00:02:52, Serial0/0/0
D 200.0.2.0/24 [90/2297856] via 54.1.1.254, 00:02:52, Serial0/0/0
D 200.0.3.0/24 [90/2297856] via 54.1.1.254, 00:02:52, Serial0/0/0
After my solution:
Rack1R6(config-router)#do sh ip route | i 54.1.1
D 200.0.0.0/24 [90/2297856] via 54.1.1.254, 00:07:40, Serial0/0/0
C 54.1.1.0 is directly connected, Serial0/0/0
D 200.0.2.0/24 [90/2297856] via 54.1.1.254, 00:07:40, Serial0/0/0
The WB solution is "access-list 1 permit 0.0.0.0 255.255.254.255". I understand my solution only works for the routes currently being received, so if it were to talk about routes that may be added in the future, my solution would not be sufficient. Would it be OK for this task, however?